document.write( "Question 119381: \r
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document.write( "How much pure alcohol must be added to 40 oz of a 25%
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document.write( "solution to produce a mixture that is 40% alcohol? \n" );
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Algebra.Com's Answer #87455 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How much pure alcohol must be added to 40 oz of a 25% \n" ); document.write( "solution to produce a mixture that is 40% alcohol? \n" ); document.write( "----------------- \n" ); document.write( "25% solution DATA: \n" ); document.write( "Amt = 40 oz ; amt of active ingredient = 0.25*40 = 10 oz \n" ); document.write( "------------------- \n" ); document.write( "Pure solution DATA: \n" ); document.write( "Amt = x oz ; amt of active ingredient = 100%*x = x oz \n" ); document.write( "----------------- \n" ); document.write( "40% Mixture DATA: \n" ); document.write( "amt. = 40+x oz ; amt of active ingredient = 0.40(40+x)=16+0.4x oz \n" ); document.write( "=================== \n" ); document.write( "EQUATION: \n" ); document.write( "active + active = active \n" ); document.write( "10 + x = 16 + 0.4x \n" ); document.write( "0.6x = 6 \n" ); document.write( "x = 10 oz (amt. of 100% alcohol needed for the mixture) \n" ); document.write( "=========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |