document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=119379>Question 119379</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "Science and medicine. A passenger train can travel 325 mi in the same time a<BR>\n" );
document.write( "freight train takes to travel 200 mi. If the speed of the passenger train is 25 mi/h<BR>\n" );
document.write( "faster than the speed of the freight train, find the speed of each. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #87454 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=87454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> seeing as the times are the same we have the following equation<BR>\n" );
document.write( "325/(r+25)=200/r cross multiplying we get:<BR>\n" );
document.write( "325r=200(r+25)<BR>\n" );
document.write( "325r=200r+5000<BR>\n" );
document.write( "325r-200r=5000<BR>\n" );
document.write( "125r=5000<BR>\n" );
document.write( "r=5000/25<BR>\n" );
document.write( "r=40 mph for the slower train.<BR>\n" );
document.write( "40+25=65 for the faster train.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "325/65=200/40<BR>\n" );
document.write( "5=5\r<BR>\n" );
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