document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=119349>Question 119349</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve this equation?  I think you have to multiply one of them by a negative and add them together, but I'm unsure.  Please advise.\r<BR>\n" );
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document.write( "2x + 3y = 4<BR>\n" );
document.write( "3x + 2y = 6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #87447 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=87447\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> MULTIPLY THE FIRST EQUATION BY 3 THEN MULTIPLY THE SECOND EQUATION BY -2 & ADD THEM.<BR>\n" );
document.write( "6X+9Y=12<BR>\n" );
document.write( "-6X-4Y=-12<BR>\n" );
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document.write( "5Y=0<BR>\n" );
document.write( "Y=0 ANSWER.<BR>\n" );
document.write( "6X+9*0=12<BR>\n" );
document.write( "6X=12<BR>\n" );
document.write( "X=12/6<BR>\n" );
document.write( "X=2 ANSWER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "3*2+2*0=6<BR>\n" );
document.write( "6=6  </SPAN>\n" );
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