document.write( "Question 119349: How do you solve this equation? I think you have to multiply one of them by a negative and add them together, but I'm unsure. Please advise.\r
\n" ); document.write( "\n" ); document.write( "2x + 3y = 4
\n" ); document.write( "3x + 2y = 6 \n" ); document.write( "
Algebra.Com's Answer #87446 by ankor@dixie-net.com(22740)\"\" \"About 
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2x + 3y = 4
\n" ); document.write( "3x + 2y = 6
\n" ); document.write( ":
\n" ); document.write( "Adding these will not help anything. We want the value of x or y in both equations
\n" ); document.write( "to be equal, they can have opposite signs, then we can add, or same signs we can subtract
\n" ); document.write( ":
\n" ); document.write( "Lets try to get y to have the same value
\n" ); document.write( "Mult equation 1 by 2, and equation 2 by 3:
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\n" ); document.write( "4x + 6y = 8
\n" ); document.write( "9x + 6y = 18
\n" ); document.write( "-----------------subtracting will eliminate y, we can solve for x
\n" ); document.write( "-5x + 0y = -10
\n" ); document.write( "+5x = +10; multiplied both side by -1 to get rid of the negatives
\n" ); document.write( "x = 10/2
\n" ); document.write( "x = 5
\n" ); document.write( ":
\n" ); document.write( "Use the 1st original equation to find y. Substitute 5 for x
\n" ); document.write( "2(5) + 3y = 4
\n" ); document.write( "10 + 3y = 4
\n" ); document.write( "3y = 4 - 10
\n" ); document.write( "3y = -6
\n" ); document.write( "y = -6/3
\n" ); document.write( "y = -2
\n" ); document.write( ":
\n" ); document.write( "Use the 2nd original equation to confirm out solutions
\n" ); document.write( "3x + 2y = 6
\n" ); document.write( "3(5) + 2(-2) =
\n" ); document.write( "10 - 4 = 10 confirms our solution
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