document.write( "Question 119186: 2/a²-2a minus 3/a²-a-2 \n" ); document.write( "

Algebra.Com's Answer #87425 by Fombitz(32388) $\"\"$ $\"About$

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$\"2%2F%28a%5E2-2a%29-3%2F%28a%5E2-a-2%29\"$
\n" ); document.write( "Whenever you subtract fractions, you need to have the same denominators.
\n" ); document.write( "Let's look at each denominator first.
\n" ); document.write( " $\"D%5B1%5D=a%5E2-2a=a%28a-2%29\"$
\n" ); document.write( " $\"D%5B2%5D=a%5E2-a-2=%28a%2B1%29%28a-2%29\"$
\n" ); document.write( "So if you multiply the first denominator by (a+1) and then second denominator by (a), they will have a common denominator of a(a+1)(a-2).
\n" ); document.write( "Remember whatever you multiply the denominator by, you also must multiply the numerator by.
\n" ); document.write( " $\"2%2F%28a%5E2-2a%29-3%2F%28a%5E2-a-2%29=2%2F%28a%28a-2%29%29-3%2F%28%28a%2B1%29%28a-2%29%29\"$
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\n" ); document.write( " $\"2%2F%28a%5E2-2a%29-3%2F%28a%5E2-a-2%29=%282%28a%2B1%29-3a%29%2F%28a%28a%2B1%29%28a-2%29%29\"$
\n" ); document.write( " $\"2%2F%28a%5E2-2a%29-3%2F%28a%5E2-a-2%29=%282a%2B2-3a%29%2F%28a%28a%2B1%29%28a-2%29%29\"$
\n" ); document.write( " $\"2%2F%28a%5E2-2a%29-3%2F%28a%5E2-a-2%29=%282-a%29%2F%28a%28a%2B1%29%28a-2%29%29\"$
\n" ); document.write( " $\"2%2F%28a%5E2-2a%29-3%2F%28a%5E2-a-2%29=%28-%28a-2%29%29%2F%28a%28a%2B1%29%28a-2%29%29\"$
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\n" ); document.write( " $\"2%2F%28a%5E2-2a%29-3%2F%28a%5E2-a-2%29=%28-1%29%2F%28a%28a%2B1%29%29\"$
\n" ); document.write( "Remember this relation only makes sense when a does not equal 0,-1,or 2. \n" ); document.write( "

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