document.write( "Question 119330: If a die is tossed twice the probability of getting 3 on both tosses is? \n" ); document.write( "

Algebra.Com's Answer #87422 by solver91311(24713) $\"\"$ $\"About$

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The die, presuming it is a fairly constructed die, has 6 different numbers, 1 through 6, with any of the six results equally likely for any given throw. Since only one of the numbers, 3, is considered a success for each of the two throws, the probability that a 3 comes up on the first throw is $\"1%2F6\"$ . The probability of a 3 on the second throw is also $\"1%2F6\"$ . The two events are independent, meaning that the outcome of the second does not depend on the outcome of the first. Therefore the combined probability is the product of the two individual probabilities, $\"%281%2F6%29%281%2F6%29=1%2F36\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Super-Double-Plus Extra Credit
\n" ); document.write( "How does the probabilility calculation change, if at all, if you rolled two dice with success being defined as double threes?\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps,
\n" ); document.write( "John \n" ); document.write( "

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