document.write( "Question 119225This question is from textbook Algebra 2
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document.write( ": It costs (20 + x) dollars to produce (x) number of products. If the products sell for (300 - 2x) dollars each, how many products should be produced each month to maximize profit? \n" );
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Algebra.Com's Answer #87390 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! It costs (20 + x) dollars to produce (x) number of products. If the products sell for (300 - 2x) dollars each, how many products should be produced each month to maximize profit? \n" ); document.write( ": \n" ); document.write( "Organize what we know here: \n" ); document.write( ": \n" ); document.write( "Cost for x items = (20+x) \n" ); document.write( ": \n" ); document.write( "Revenue per item = (300-2x) \n" ); document.write( "Revenue for x items = x(300-x) \n" ); document.write( ": \n" ); document.write( "We know that profit is: Revenue - cost: \n" ); document.write( "Write that equation where y = profit on x items \n" ); document.write( "y = x(300-2x) - (20+x) \n" ); document.write( "y = 300x - 2x^2 - 20 - x \n" ); document.write( "y = 280x - 2x^2 - x \n" ); document.write( "write it as a quadratic equation: \n" ); document.write( "y = -2x^2 + 279x \n" ); document.write( ": \n" ); document.write( "Maximum profit occurs at the axis of symmetry, we can find that using \n" ); document.write( "x = \n" ); document.write( "x = \n" ); document.write( "x = \n" ); document.write( "x = +69.75 items \n" ); document.write( "We can't make .75 items, so say max profit when 70 items are made \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Did this make sense to you? Let me know. \n" ); document.write( " \n" ); document.write( " |