document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=119304>Question 119304</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the area of the right triangle that satisfies the conditions and approximate the values to the nearest tenth: shorter leg is 40 centimeters and hypotenuse twice the shorter leg? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #87385 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=87385\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the area of the right triangle whose base is 40cm and whose hypotenuse is twice the base or 80cm.<BR>\n" );
document.write( "We will need to find the length of the third leg, or the height, of the triangle before we can find the area.<BR>\n" );
document.write( "Using the Pythagorean theorem <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%5E2+=+a%5E2%2Bb%5E2 ALIGN=MIDDLE  ALT=\"c%5E2+=+a%5E2%2Bb%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > where the hypotenuse, c = 80, the base, a = 40, and b is h, the height.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=80%5E2+=+40%5E2%2Bh%5E2 ALIGN=MIDDLE  ALT=\"80%5E2+=+40%5E2%2Bh%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6400+=+1600%2Bh%5E2 ALIGN=MIDDLE  ALT=\"6400+=+1600%2Bh%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 1600 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4800+=+h%5E2 ALIGN=MIDDLE  ALT=\"4800+=+h%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the square root of both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h+=+40sqrt%283%29 ALIGN=MIDDLE  ALT=\"h+=+40sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now we can calculate the area of the triangle which is given by:<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+%281%2F2%29bh ALIGN=MIDDLE  ALT=\"A+=+%281%2F2%29bh\"   DISABLED_style= \"max-width:90%; height:auto;\" > where b is the length of the base or 40cm and h is the height, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h+=+40sqrt%283%29 ALIGN=MIDDLE  ALT=\"h+=+40sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Making the apprpriate substitutions, we get:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+%281%2F2%29%2840%29%2840sqrt%283%29%29 ALIGN=MIDDLE  ALT=\"A+=+%281%2F2%29%2840%29%2840sqrt%283%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplifying this...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+800sqrt%283%29 ALIGN=MIDDLE  ALT=\"A+=+800sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "To the nearest tenth, this would be:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+800%281.7321%29 ALIGN=MIDDLE  ALT=\"A+=+800%281.7321%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+1385.7 ALIGN=MIDDLE  ALT=\"A+=+1385.7\"   DISABLED_style= \"max-width:90%; height:auto;\" >sq.cm </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );