document.write( "Question 119291: at the beginning of the Alay Lakad, Rizza and Angel are 30km apart. if they leave at the same time and walk in the same direction, rizza overtakes angel in 60 hours. if they walk towards to each other, they meet in 5 hours. what are their speed? \n" ); document.write( "
Algebra.Com's Answer #87370 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! R and A are 30km apart. if they leave at the same time and walk in the same direction, R overtakes A in 60 hours. if they walk towards to each other, they meet in 5 hours. what are their speed? \n" ); document.write( ": \n" ); document.write( "r = R's speed \n" ); document.write( "and \n" ); document.write( "a = A's speed \n" ); document.write( ": \n" ); document.write( "Write a distance equation for each trip, Distance = time * speed: \n" ); document.write( ": \n" ); document.write( "Same direction: \n" ); document.write( "60r - 30 = 60a \n" ); document.write( "60r - 60a = 30 \n" ); document.write( "r - s = .5; simplified divided equation by 60 \n" ); document.write( ": \n" ); document.write( "Toward each other (total both traveled = 30 km) \n" ); document.write( "5r + 5a = 30 \n" ); document.write( "r + a = 6; simplified, divided equation by 5 \n" ); document.write( ": \n" ); document.write( "Use these two equation for elimination of a: \n" ); document.write( "r + a = 6 \n" ); document.write( "r - a = .5 \n" ); document.write( "--------------add \n" ); document.write( "2r +0a = 6.5 \n" ); document.write( "r = \n" ); document.write( "r = 3.25 km/h is R's speed \n" ); document.write( ": \n" ); document.write( "Use r - a = .5 to find a's speed \n" ); document.write( "3.25 - a = .5 \n" ); document.write( "-a = .5 - 3.25 \n" ); document.write( "-a = -2.75 \n" ); document.write( "a = 2.75 km/h is A's speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions in original equations \n" ); document.write( "60r - 60a = 30 \n" ); document.write( "60(3.25) - 60(2.75) = \n" ); document.write( "195 - 165 = 30 \n" ); document.write( "and \n" ); document.write( "5r + 5a = 30 \n" ); document.write( "5(3.25) + 5(2.75) = \n" ); document.write( "16.25 + 13.75 = 30; confirms our solutions \n" ); document.write( ": \n" ); document.write( "Did this make sense to you? Any questions?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |