document.write( "Question 18134: If you could please let me know if I have this right, there is no example of this kind of particular problem in my book.\r
\n" ); document.write( "\n" ); document.write( "Solve the equation: \"+5%2Fx+-+3%2Fx+=+3+\"\r
\n" ); document.write( "\n" ); document.write( "This is what I did, but I am not sure it is correct.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%29+5%2Fx+-+%28x%29+3%2Fx+=++%28x%29+3%2F1+\"\r
\n" ); document.write( "\n" ); document.write( "\"5x+-+3x+=+3x\"
\n" ); document.write( " -2 = 3x
\n" ); document.write( " \"-2%2F3+=+x\"\r
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\n" ); document.write( "\n" ); document.write( "If you could please let me know if i did this correctly, i would appreciate it from the bottom of my heart and the top of my grades.\r
\n" ); document.write( "\n" ); document.write( "Thanks ever so much,\r
\n" ); document.write( "\n" ); document.write( "Lizzy
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Algebra.Com's Answer #8736 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well...think about this, you are subtracting two fractions \"5%2Fx\" and \"3%2Fx\" and you'll notice that they have a common the denominator of x, so, you can just subtract the two fractions.\r
\n" ); document.write( "\n" ); document.write( "\"5%2Fx+-+3%2Fx+=+3\"
\n" ); document.write( "\"%285-3%29%2Fx+=+3\"
\n" ); document.write( "\"2%2Fx+=+3\" Multiply both sides by x.
\n" ); document.write( "\"2+=+3x\" Finally, divide both sides by 3.
\n" ); document.write( "\"2%2F3+=+x\"\r
\n" ); document.write( "\n" ); document.write( "The solution is \"x+=+2%2F3\"\r
\n" ); document.write( "\n" ); document.write( "Check: \"5%2F%282%2F3%29+-+3%2F%282%2F3%29+=+15%2F2+-+9%2F2\" = \"%2815-9%29%2F2+=+6%2F2\" = 3 OK.
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