document.write( "Question 119211: 256x^2 = 36
\n" ); document.write( "a. -3/8, 3/8
\n" ); document.write( "b.-9/64,9/64
\n" ); document.write( "c.-8/3,8/3
\n" ); document.write( "d. -64/9,64/9
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Algebra.Com's Answer #87310 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"256x%5E2+=+36\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+36%2F256\" Divide both sides by 256\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%2836%2F256%29\" Take the square root of both sides. I can't type in the plus/minus symbol, but just remember that there's a negative solution as well.\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%2836%29%2Fsqrt%28256%29\" Break up the square root\r
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\n" ); document.write( "\n" ); document.write( "\"x=%286%29%2Fsqrt%28256%29\" Simplify \"sqrt%2836%29\" to get \"6\" \r
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\n" ); document.write( "\n" ); document.write( "\"x=%286%29%2F%2816%29\" Simplify \"sqrt%28256%29\" to get \"16\" \r
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\n" ); document.write( "\n" ); document.write( "\"x=3%2F8\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "Remember, there's a negative portion as well. So the solution is \r
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\n" ); document.write( "\n" ); document.write( "\"x=3%2F8\" or \"x=-3%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "So the answer is A)
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