document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=119199>Question 119199</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to simplify the expression, I have the right number but still very confused how I got the answer. Could you give me the steps to do this? Thanks so much.. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2%283a%2B1%29-1%2F3%28a-5%29 ALIGN=MIDDLE  ALT=\"1%2F2%283a%2B1%29-1%2F3%28a-5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > The answer is 7/6a+13/6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #87300 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=87300\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/[2(3a+1)] - 1/[3(a-5)]<BR>\n" );
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document.write( "Least common denominator: 6(a-5)(3a+1)\r<BR>\n" );
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document.write( "Rewrite each fraction with the lcm as its denominator:\r<BR>\n" );
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document.write( "[3(a-5)]/lcm - [2(3a+1)]/lcm\r<BR>\n" );
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document.write( "Combine the fractions:\r<BR>\n" );
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document.write( "= [3a-15-6a-2]/lcm\r<BR>\n" );
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document.write( "= [-3a-17]/[6(a-5)(3a+1)]\r<BR>\n" );
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document.write( "=============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "  </SPAN>\n" );
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