document.write( "Question 119194: Solve \r
\n" ); document.write( "\n" ); document.write( "x^2+6x+9=49\r
\n" ); document.write( "\n" ); document.write( "a.4,-4
\n" ); document.write( "b.10,-4
\n" ); document.write( "c.4, -10
\n" ); document.write( "d.10,-10
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Algebra.Com's Answer #87285 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2%2B6x%2B9=49\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B6x%2B9-49=0\" Subtract 49 from both sides. \r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B6x-40=0\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B10%29%28x-4%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"x%2B10=0\" or \"x-4=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"x=-10\" or \"x=4\" Now solve for x in each case\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \r
\n" ); document.write( "\n" ); document.write( " \"x=-10\" or \"x=4\" \r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"y=x%5E2%2B6x-40\" we can see that the roots are \"x=-10\" and \"x=4\" . So this visually verifies our answer.\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28500%2C500%2C-12%2C10%2C-10%2C10%2C0%2C+x%5E2%2B6x-40%29+\"\r
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\n" ); document.write( "\n" ); document.write( "So the answer is C)
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