document.write( "Question 119138: Angles G and H are complementary. If \"m%3CG=3x%2B6+and+m%3CH=2x-11\", what is the measure of each angle? \n" ); document.write( "
Algebra.Com's Answer #87245 by jim_thompson5910(35256)\"\" \"About 
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Since they are complementary, the angles add to 90 ie \"G%2BH=90\"\r
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\n" ); document.write( "\n" ); document.write( "So \"3x%2B6%2B2x-11=90\"\r
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\n" ); document.write( "\n" ); document.write( "\"5x-5=90\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"5x=90%2B5\"Add 5 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"5x=95\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2895%29%2F%285%29\" Divide both sides by 5 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=19\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So the value of x is \"x=19\" \r
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\n" ); document.write( "\n" ); document.write( "\"G=3x%2B6\" Start with the first angle\r
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\n" ); document.write( "\n" ); document.write( "\"G=3%2819%29%2B6\" Plug in \"x=19\"\r
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\n" ); document.write( "\n" ); document.write( "\"G=57%2B6\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"G=63\" Add\r
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\n" ); document.write( "\n" ); document.write( "So the first angle is \"G=63\" \r
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\n" ); document.write( "\n" ); document.write( "\"H=2x-11\" Start with the second angle\r
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\n" ); document.write( "\n" ); document.write( "\"H=2%2819%29-11\" Plug in \"x=19\"\r
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\n" ); document.write( "\n" ); document.write( "\"H=38-11\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"H=27\" Subtract\r
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\n" ); document.write( "\n" ); document.write( "So the second angle is \"H=27\" \r
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\n" ); document.write( "\n" ); document.write( "So our two angles are \"G=63\" and \"H=27\"
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