document.write( "Question 119124: Find the indicated root
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Algebra.Com's Answer #87223 by jim_thompson5910(35256)\"\" \"About 
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\"sqrt%28121m%5E8n%5E4%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28121%29%5E1m%5E8n%5E4%29%5E%281%2F2%29\" Rewrite the square root in exponent notation. Note: \"121\" really looks like \"121%5E1\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28121%29%5E%281%2A%281%2F2%29%29m%5E%288%2A%281%2F2%29%29n%5E%284%2A%281%2F2%29%29\" Now distribute the outer exponent \"1%2F2\" to each exponent in the parenthesis. Remember \"%28x%5Ey%29%5Ez=x%5E%28y%2Az%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28121%29%5E%281%2F2%29m%5E%288%2F2%29n%5E%284%2F2%29\" Now multiply the exponents\r
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\n" ); document.write( "\n" ); document.write( "\"%28121%29%5E%281%2F2%29m%5E4n%5E2\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28121%29m%5E4n%5E2\" Now rewrite \"%28121%29%5E%281%2F2%29\" as \"sqrt%28121%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"11m%5E4n%5E2\" Take the square root of 121 to get 11\r
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\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"sqrt%28121m%5E8n%5E4%29\" simplifies to \"11m%5E4n%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"sqrt%28121m%5E8n%5E4%29=11m%5E4n%5E2\".
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