document.write( "Question 119096: For what value(s) of 'p' would the equation px^2 + (2p+1)x+p=0 have two non-real roots? I think it is p=-1/4 but I'm only guessing. \n" ); document.write( "
Algebra.Com's Answer #87217 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
From the quadratic formula\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the discriminant consists of all of the terms in the square root. So the discriminant is\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D=b%5E2-4ac\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the discriminant tells us how many solutions (and what type of solutions) we can expect for any quadratic. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So let's find the discriminant for \"px%5E2+%2B+%282p%2B1%29x%2Bp\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D=%282p%2B1%29%5E2-4%2Ap%2Ap\" Plug in \"a=p\", \"b=2p%2B1\", \"c=p\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D=4p%5E2%2B4p%2B1-4p%5E2\" Foil and multiply\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D=4p%2B1\" Combine like terms\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now since we want to have 2 non-real solutions, this means \"D%3C0\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3p%2B1%3C0\" Set the discriminant less than zero\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4p%3C0-1\"Subtract 1 from both sides\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4p%3C-1\" Combine like terms on the right side\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"p%3C%28-1%29%2F%284%29\" Divide both sides by 4 to isolate p \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"p%3C-1%2F4\" Reduce\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So our answer is \"p%3C-1%2F4\" (which is approximately \"p%3C-0.25\" in decimal form)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So you're on the right track, but you have to remember that values such as \"p=-10\" work also since -10 is less than \"-1%2F4\"
\n" ); document.write( "
\n" ); document.write( "
\n" );