document.write( "Question 119012: use synthetic substitution to evaluate the polynomial for the given value\r
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document.write( "p(x)=25x²-16 for x=4/5 \n" );
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Algebra.Com's Answer #87205 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! p(x)=25x²-16 for x=4/5 \n" ); document.write( "=25(4/5)^2-16 \n" ); document.write( "=25(16/25)-16 \n" ); document.write( "=16-16 \n" ); document.write( "=0 \n" ); document.write( ". \n" ); document.write( "so, \n" ); document.write( "P(4/5)=0 \n" ); document.write( " |