document.write( "Question 119012: use synthetic substitution to evaluate the polynomial for the given value\r
\n" ); document.write( "\n" ); document.write( "p(x)=25x²-16 for x=4/5
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Algebra.Com's Answer #87205 by tutorcecilia(2152)\"\" \"About 
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p(x)=25x²-16 for x=4/5
\n" ); document.write( "=25(4/5)^2-16
\n" ); document.write( "=25(16/25)-16
\n" ); document.write( "=16-16
\n" ); document.write( "=0
\n" ); document.write( ".
\n" ); document.write( "so,
\n" ); document.write( "P(4/5)=0
\n" ); document.write( "
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