document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=18096>Question 18096</A>: <I><SPAN STYLE=\"word-break: break-all;\"> perimeter of rectangle is 64 centimeters   length is 4 centimeters less than twice the width   what is lenght and width?  thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8717 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8717\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> perimeter of rectangle is 64 centimeters   length is 4 centimeters less than twice the width   what is lenght and width?  thanks<BR>\n" );
document.write( "let the width be x..twice width=2x...4 cm. less than that =2x-4<BR>\n" );
document.write( "perimeter =2(length+width)=64<BR>\n" );
document.write( "2(x+2x-4)=64<BR>\n" );
document.write( "2(3x-4)=64<BR>\n" );
document.write( "6x-8=64<BR>\n" );
document.write( "6x=64+8=72<BR>\n" );
document.write( "x=72/6=12<BR>\n" );
document.write( "so width is 12 cm and length is 2*12-4=20 cm.<BR>\n" );
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