document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=18095>Question 18095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Here's another one:<BR>\n" );
document.write( "sqrt(13-x) = x-1\r<BR>\n" );
document.write( "\n" );
document.write( "  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8715 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8715\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt(13-x) = x-1\r<BR>\n" );
document.write( "\n" );
document.write( "square both sides<BR>\n" );
document.write( "13-x=(x-1)^2=x^2+1-2x<BR>\n" );
document.write( "x^2+1-2x-13+x=0<BR>\n" );
document.write( "x^2-x-12=0<BR>\n" );
document.write( "find the product of coefficients of x^2 term(1 here)and constant term(-12 here)=-12..now find 2 factors for this whose sum is coefficient of x term(-1 here)..they are -4 and +3...so<BR>\n" );
document.write( "x^2-4x+3x-12=0<BR>\n" );
document.write( "x(x-4)+3(x-4)=0<BR>\n" );
document.write( "(x-4)(x+3)=0<BR>\n" );
document.write( "so x=4 or -3<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );