document.write( "Question 119027This question is from textbook U of Phoenix elementry and intermediate algebra
\n" ); document.write( ": I know its got to be simple, but I just don't understand quadratic equations. 12x^+5x-3=0 ^=squared \n" ); document.write( "

Algebra.Com's Answer #87136 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
12x^2+5x-3=0
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\n" ); document.write( "Solved by graphing:
\n" ); document.write( " $\"graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C12x%5E2%2B5x-3%29\"$
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\n" ); document.write( "Solved by factoring:
\n" ); document.write( "12x^2+9x-4x-3=0
\n" ); document.write( "3x(4x+3)-(4x+3)=0
\n" ); document.write( "(4x+3)(3x-1)=0
\n" ); document.write( "4x+3=0 or 3x-1=0
\n" ); document.write( "x = -3/4 or x = 1/3
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\n" ); document.write( "Solved by the quadratic formula:
\n" ); document.write( "x = [-5 +- sqrt(5^2-4*12*-3)]/(2*12)
\n" ); document.write( "x = [-5 +- sqrt(169)]/24
\n" ); document.write( "x = [-5 +- 13]/24
\n" ); document.write( "x = [-5+13]/24 or x = [-5-13]/24
\n" ); document.write( "x = 1/3 or x = -3/4
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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