document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118880>Question 118880</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780073268620/algebrahomeworkh>Elementary and Intemediate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "x+3 divided by x < or equal to -2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #87109 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=87109\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+3)/x<=-2 cross multiply.<BR>\n" );
document.write( "x+3<=-2x<BR>\n" );
document.write( "x+2x<=-3<BR>\n" );
document.write( "3x<=-3<BR>\n" );
document.write( "x<=-3/3<BR>\n" );
document.write( "x<=-1 answer.<BR>\n" );
document.write( "proof.<BR>\n" );
document.write( "let x=-1.1<BR>\n" );
document.write( "(-1.1+3)/-1.1<=-2<BR>\n" );
document.write( "1.9/-1.1<=-2<BR>\n" );
document.write( "-1.72<=-2 </SPAN>\n" );
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