document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=18080>Question 18080</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of 3 numbers is 137.  The second number is 4 more than 2 times the first number.  The third is 5 less than three times the first number.  Find the 3 numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8710 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of 3 numbers is 137.  The second number is 4 more than 2 times the first number.  The third is 5 less than three times the first number.  Find the 3 numbers<BR>\n" );
document.write( "let the 1st.number=x<BR>\n" );
document.write( "two times this number=2x..and 4 more than this =2x+4=second number.<BR>\n" );
document.write( "three times the first number =3x...and 5 less than this =3x-5=third number<BR>\n" );
document.write( "sum of the 3 numbers=x+2x+4+3x-5=137<BR>\n" );
document.write( "6x=137-4+5=138<BR>\n" );
document.write( "x=138/6=23<BR>\n" );
document.write( "so the three numbers are 23,2*23+4=50,and 3*23-5=64<BR>\n" );
document.write( "23,50 and 64 is the answer. </SPAN>\n" );
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