document.write( "Question 118915: 4. Solve
\n" ); document.write( " x + y - z = 0
\n" ); document.write( " 2x - y + z = 6
\n" ); document.write( " -x + y + z = 8
\n" ); document.write( "Show your answers as (x,y,z) \r
\n" ); document.write( "\n" ); document.write( "PLEASE SHOW ALL WORK
\n" ); document.write( "THANK YOU
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Algebra.Com's Answer #87064 by mayank(15)\"\" \"About 
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let x+y-z=0 ---1
\n" ); document.write( "and 2x-y+z=6 ---2
\n" ); document.write( "and -x+y+z=8 ---3\r
\n" ); document.write( "\n" ); document.write( "now adding 1 and 3 gives 2y=8
\n" ); document.write( "thus y=4 ---4\r
\n" ); document.write( "\n" ); document.write( "putting value of y in eq 1 gives x+4-z=0
\n" ); document.write( "thus x-z=-4-----5\r
\n" ); document.write( "\n" ); document.write( "now putting value of y in eq 2 gives 2x-4+z=6
\n" ); document.write( "thus 2x+z=10---6\r
\n" ); document.write( "\n" ); document.write( "Adding eq 5 and 6 we get,\r
\n" ); document.write( "\n" ); document.write( "3x=6
\n" ); document.write( "thus x=2 ----7\r
\n" ); document.write( "\n" ); document.write( "putting values of x and y in eq 1 gives 2+4-z=0\r
\n" ); document.write( "\n" ); document.write( "thus 6-z=0
\n" ); document.write( "thus z=6-----8\r
\n" ); document.write( "\n" ); document.write( "thus from eq 4,7 and 8 we get x,y,z as 2,4 and 6 respectively
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