document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118949>Question 118949</A>: <I><SPAN STYLE=\"word-break: break-all;\"> many likes to buy two different kinds of strings for the guitar . the slinky costs $3.50 for each set and the slippys cost $4.50 for each set. how many of the slippys did he buy if he spent $41 ona total of $10 sets of strings. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #87055 by </B><A HREF=/tutors/aboutme.mpl?userid=mayank><B>mayank(15)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mayank><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=87055\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the no. of slinky sets purchased be x and no. of slippy sets purchased be y.\r<BR>\n" );
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document.write( "Then,3.5x+4.5y=41<BR>\n" );
document.write( "and as total sets is 10, x+y=10\r<BR>\n" );
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document.write( "Multiplying eq 2 by 3.5 we get 3.5x+3.5y=35\r<BR>\n" );
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document.write( "thus, subtracting eq 2 from 1 we get,<BR>\n" );
document.write( "y=6\r<BR>\n" );
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document.write( "thus no. of slippy sets is 6. </SPAN>\n" );
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