document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118931>Question 118931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a canoeist paddled for 4 hrs with a 6km/h current to reach a campsite.the return trip against the same current took 10 hrs.find the speed of the canoe in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #87052 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=87052\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> DISTANCE=RATE*TIME<BR>\n" );
document.write( "GOING WE HAVE D=4(S+6) WHERE S=SPEED OF THE CANOEIST.<BR>\n" );
document.write( "RETURNING WE HAVE D=10(S-6)<BR>\n" );
document.write( "SETTING THESE 2 EQUATIONS EQUAL WE GET:<BR>\n" );
document.write( "4(S+6)=10(S-6)<BR>\n" );
document.write( "4S+24=10S-60<BR>\n" );
document.write( "4X-10S=-60-24<BR>\n" );
document.write( "-6S=-84<BR>\n" );
document.write( "S=-84/-6<BR>\n" );
document.write( "S=14 KMH IS THE CANOEIST SPEED.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "4(14+6)=10(14-6)<BR>\n" );
document.write( "4*20=10*8<BR>\n" );
document.write( "80=80<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );