document.write( "Question 118961: Hello can you help me with this questions please.
\n" ); document.write( "Suppose that the width of a rectangle is 5 inches shorter than the lenght and that the perimeter of the rectangle is 50.
\n" ); document.write( "a) Set up an equation of the perimeter involving only L, the length of the rectangle.
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\n" ); document.write( "b) Solve this equation algebraically to find the length of the rectangle. Find the width as well.
\n" ); document.write( "Answer: Length ______, Width ______
\n" ); document.write( "Show your work here:\r
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Algebra.Com's Answer #87040 by mayank(15)\"\" \"About 
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here let width be W and length be L
\n" ); document.write( "From given details width is 5 inches shorter than length, thus W=L-5\r
\n" ); document.write( "\n" ); document.write( "now perimeter of rectangle is 50.
\n" ); document.write( "thus 50=2(L+W)\r
\n" ); document.write( "\n" ); document.write( "thus P=2(L+L-5)
\n" ); document.write( "thus P=2(2L-5)
\n" ); document.write( "thus P=4L-10\r
\n" ); document.write( "\n" ); document.write( "b)now as p=50, 50=4L-10;
\n" ); document.write( "thus 60=4L
\n" ); document.write( "thus L=60/4
\n" ); document.write( "thus L=15
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