document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118942>Question 118942</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the first three terms of an arithmetic sequence are (2x+1,4x+2,10x-1,...), what is the value of x? Please can someone explain ? I think the answer is 1 but I don't really understand this question. </SPAN>\n" );
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document.write( "Ans.The answer to the above question is x=1. It is because as the given three terms are in arithmetic sequence, the difference betweent two consecutive terms remains constant and same.Thus 2nd term-1st term= 3rd term-2nd term.Therefore,<BR>\n" );
document.write( "4x+2-(2x+1)=10x-1-(4x+2)<BR>\n" );
document.write( "thus,4x+2-2x-1=10x-1-4x-2<BR>\n" );
document.write( "thus 2x+1=6x-3<BR>\n" );
document.write( "thus 4x=4<BR>\n" );
document.write( "and this leads to x=1. </SPAN>\n" );
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