document.write( "Question 118925: I have plugged this one into the solver and that confused me even more.
\n" ); document.write( "Solve by completing the square:
\n" ); document.write( "x^2 + 8x + 13 = 0\r
\n" ); document.write( "\n" ); document.write( "I get to (x+4)^2 =3 and then I hit a wall.\r
\n" ); document.write( "\n" ); document.write( "Please help!!\r
\n" ); document.write( "\n" ); document.write( "You guys are great and thank you in adavnce for your help.
\n" ); document.write( "

Algebra.Com's Answer #87016 by tutor_paul(519)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2%2B8x%2B13=0\"
\n" ); document.write( "First, get all the x terms on one side of the equation:
\n" ); document.write( "\"x%5E2%2B8x=-13\"
\n" ); document.write( "Divide the coefficient of x by 2 and square the result. Add this result to both sides of the equation:
\n" ); document.write( "\"x%5E2%2B8x%2B16=-13%2B16\"
\n" ); document.write( "Simplify right side of the equation:
\n" ); document.write( "\"x%5E2%2B8x%2B16=3\"
\n" ); document.write( "Express the right side as a perfect square:
\n" ); document.write( "\"%28x%2B4%29%5E2=3\"
\n" ); document.write( "Remember the goal is to solve for x. Take the square root of both sides of the equation:
\n" ); document.write( "(x+4)=+-sqrt(3)
\n" ); document.write( "Since this is a second order equation, x can assume 2 values. Take the case of the \"%2Bsqrt%283%29\" first and solve for x:
\n" ); document.write( "\"x%2B4=sqrt%283%29\"
\n" ); document.write( "\"highlight%28x=sqrt%283%29-4%29\"
\n" ); document.write( "Now, take the case of \"-sqrt%283%29\":
\n" ); document.write( "\"x%2B4=-sqrt%283%29\"
\n" ); document.write( "\"highlight%28x=-sqrt%283%29-4%29\"
\n" ); document.write( "Plug each of these results into the original equation to check and see if they are right.
\n" ); document.write( "==================
\n" ); document.write( "good Luck,
\n" ); document.write( "tutor_paul@yahoo.com\r
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