document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118819>Question 118819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the quadratic equation x^2-15=2k(x-4),find k if there are two real and equal roots. I got k=5 and k=3 but I would appreciate it if someone could explain it in detail to me :) Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86994 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86994\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> expanding the equation gives x^2-15=2kx-8k ___ x^2-2kx+8k-15=0\r<BR>\n" );
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document.write( "for the quadratic to be a \"perfect square\", (b/2)^2=c ___ so (-2k/2)^2=8k-15\r<BR>\n" );
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document.write( "k^2-8k+15=0 ___ (k-5)(k-3)=0 </SPAN>\n" );
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