document.write( "Question 118872:
\n" ); document.write( " $\"2x%5E2-12=5x\"$ \n" ); document.write( "

Algebra.Com's Answer #86974 by checkley71(8403) $\"\"$ $\"About$

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2X^2-12=5X
\n" ); document.write( "2X^2-5X-12=0
\n" ); document.write( "(2X+3)(X-4)=0
\n" ); document.write( "2X+3=0
\n" ); document.write( "2X=-3
\n" ); document.write( "X=-3/2 OR -1.5 ANSWER.
\n" ); document.write( "X-4=0
\n" ); document.write( "X=4 ANSWER.
\n" ); document.write( "---------------------------------------------------------------
\n" ); document.write( "X^2-12=5X
\n" ); document.write( "X^2-5X-12=0
\n" ); document.write( "USING THE QUADRATIC EQUATIO - $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$ WE GET: X=(5+-SQRT[-5^2-4*1*-12])/2*10
\n" ); document.write( "X=(5+-SQRT[25+48])/2
\n" ); document.write( "X=(5+-SQRT73)/2
\n" ); document.write( "X=(5+-8.544)/2
\n" ); document.write( "X=(5+8.544)/2
\n" ); document.write( "X=13.544/2
\n" ); document.write( "X=6.772 ANSWER.
\n" ); document.write( "X=(5-8.544)/2
\n" ); document.write( "X=-3.544/2
\n" ); document.write( "X=-1.772 ANSWER.
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