document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118768>Question 118768</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "A picture measuring 40cm by 60cm is surrounded by a frame of uniform width. If the area of the frame equals the area of the picture,then what is the width of the frame ?<BR>\n" );
document.write( "Please help me :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86910 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86910\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 40*60=2400 CM^2 FOR THE AREA OF THE PICTURE.<BR>\n" );
document.write( "2400+2400=4800 IS THE AREA OF THE PICTURE & THE FRAME.<BR>\n" );
document.write( "(40+2X)(60+2X)=4800 <BR>\n" );
document.write( "2400+120X+80X+4X^2=4800<BR>\n" );
document.write( "4X^2+200X+2400-4800=0<BR>\n" );
document.write( "(4X^2+200X-2400)=0<BR>\n" );
document.write( "4(X^2+50X-600)=0<BR>\n" );
document.write( "4(X+60)(X-10)=0<BR>\n" );
document.write( "X-10=0<BR>\n" );
document.write( "X=10 CM IS THE WIDTH OF THE FRAME.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "(40+20)(60+20)=4800<BR>\n" );
document.write( "60*80=4800<BR>\n" );
document.write( "4800=4800\r<BR>\n" );
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