document.write( "Question 118746: \r
\n" ); document.write( "\n" ); document.write( "What are the points that lie on the line 2x + 3y + 5 = 0\r
\n" ); document.write( "\n" ); document.write( "Thank you \n" ); document.write( "
Algebra.Com's Answer #86885 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
FIRST YOU NEED TO PUT THIS EQUATION INTO THE STANDARD LINE FORMULA:
\n" ); document.write( "Y=mX+b WHERE m=SLOPE & b=THE Y INTERCEPT.
\n" ); document.write( "2X+3Y+5=0
\n" ); document.write( "3Y=-2X-5
\n" ); document.write( "Y=-2X/3-5/3
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-4%2C+4%2C+-4%2C+4%2C+y+=+-2x%2F3+-5%2F3%29+\" (graph 300x300 pixels, x from -4 to 4, y from -4 to 4, y = -2x/3 -5/3).
\n" ); document.write( "YOU NOW HAVE A SLOPE=(-2/3) & A Y INTERCEPT=(-5/3).
\n" ); document.write( "TO FIND ANY SET OF POINTS ON THIS LINE JUST SET X=0 & SOLVE FOR Y:
\n" ); document.write( "Y=-2*0-5/3
\n" ); document.write( "Y=-5/3
\n" ); document.write( "SO WE HAVE THE POINT (0,-5/3)
\n" ); document.write( "YOU CAN ALSO SET Y=0 AND SOLVE FOR X:
\n" ); document.write( "0=-2X/3-5/3
\n" ); document.write( "-2X/3=5/3 NOW CROSS MULTIPLY.
\n" ); document.write( "-6X=15
\n" ); document.write( "X=15/-6
\n" ); document.write( "X=-5/2
\n" ); document.write( "SO WE HAVE THE POINT (-5/2,0)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );