document.write( "Question 118745: find each product.\r
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Algebra.Com's Answer #86876 by jim_thompson5910(35256) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"3x%5E2%282y%2B5x%29\"$ Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( " $\"%283x%5E2%29%282y%29%2B%283x%5E2%29%285x%29\"$ Distribute $\"3x%5E2\"$ among the terms in the parenthesis\r
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\n" ); document.write( "\n" ); document.write( " $\"6x%5E2y%2B%283x%5E2%29%285x%29\"$ Multiply $\"3x%5E2\"$ and $\"2y\"$ to get $\"6x%5E2y\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"6x%5E2y%2B15x%5E3\"$ Multiply $\"3x%5E2\"$ and $\"5x\"$ to get $\"15x%5E3\"$ \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So $\"3x%5E2%282y%2B5x%29\"$ distributes to $\"6x%5E2y%2B15x%5E3\"$ \r
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\n" ); document.write( "\n" ); document.write( "In other words, $\"3x%5E2%282y%2B5x%29=6x%5E2y%2B15x%5E3\"$ \r
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