document.write( "Question 118741This question is from textbook algebra 1
\n" ); document.write( ": after you subtract 4 and are left with -d/3 < 6 how do you finish the problem? \n" ); document.write( "
Algebra.Com's Answer #86873 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"-d%2F3+%3C+6+\"......multiply both sides by \"3\"\r
\n" ); document.write( "\n" ); document.write( "\"%28-d%2F3%293+%3C+6%2A3+\"......\r
\n" ); document.write( "\n" ); document.write( "\"%28-d%2Fcross%283%29%29cross%283%29+%3C+18+\"......\r
\n" ); document.write( "\n" ); document.write( "\"-d+%3C+18+\"......divide both sides by \"-1\"....(recall: sign will change)\r
\n" ); document.write( "\n" ); document.write( "\"-d%28-1%29+%3C+18%28-1%29+\"......\r
\n" ); document.write( "\n" ); document.write( "\"d+%3E+-18\"......
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