document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118723>Question 118723</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help with this question--What is the x co-ordinate of the system of equations ?  2x + y = 3 and x - 2y = 4.\r<BR>\n" );
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document.write( "Thanking you <BR>\n" );
document.write( "Gloria </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86861 by </B><A HREF=/tutors/aboutme.mpl?userid=m.hansen><B>m.hansen(16)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=m.hansen><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86861\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x + y = 3<BR>\n" );
document.write( "x - 2y = 4\r<BR>\n" );
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document.write( ":: if we want the x coordinate, we have to get rid of the y<BR>\n" );
document.write( ":: if we multiply the top equation by 2, the y becomes 2y, <BR>\n" );
document.write( ":: which will cancel the -2y in the second equation<BR>\n" );
document.write( "top equ * 2:<BR>\n" );
document.write( "4x + 2y = 6<BR>\n" );
document.write( ":: now the new top equation and the original bottom equation<BR>\n" );
document.write( "4x + 2y = 6<BR>\n" );
document.write( "x  - 2y = 4<BR>\n" );
document.write( ":: add these two equations<BR>\n" );
document.write( "5x + 0 = 10<BR>\n" );
document.write( "5x = 10<BR>\n" );
document.write( ":: divide both sides by 5<BR>\n" );
document.write( "x = 2 </SPAN>\n" );
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