document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118719>Question 118719</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "A right-angled triangle has a perimeter of 120cm. If the hypoteneuse is 50cm, find the length of the other two sides. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86846 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86846\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A^2+b^2=c^2 &<BR>\n" );
document.write( "A+B+C=120 <BR>\n" );
document.write( "A+B+50=120 <BR>\n" );
document.write( "A+B=120-50 <BR>\n" );
document.write( "A+B=70 <BR>\n" );
document.write( "A=70-B<BR>\n" );
document.write( "Then:<BR>\n" );
document.write( "(70-B)^2+B^2=50^2<BR>\n" );
document.write( "4900-140B+B^2+B^2=2500<BR>\n" );
document.write( "2B^2-140B+4900-2500=0<BR>\n" );
document.write( "2B^2-140B+2400=0<BR>\n" );
document.write( "2(B^2-70B+1200)=0<BR>\n" );
document.write( "2(B-40)(B-30)=0<BR>\n" );
document.write( "B-40=0<BR>\n" );
document.write( "B=40 ANSWER.<BR>\n" );
document.write( "A=70-40<BR>\n" );
document.write( "A=30 ANSWER.<BR>\n" );
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