document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118700>Question 118700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the value of x when the equation is log5+logx=2? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86840 by </B><A HREF=/tutors/aboutme.mpl?userid=m.hansen><B>m.hansen(16)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=m.hansen><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86840\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log5+logx=2?\r<BR>\n" );
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document.write( "remember: logs can be combined as such: Log(x) + Log(y) -> Log(x*y)<BR>\n" );
document.write( "so: log(5) + log(x) = 2<BR>\n" );
document.write( "becomes: log(5*x)=2 or log(5x)=2\r<BR>\n" );
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document.write( "logs can be changed into exponents, and \"log\" is base 10.\r<BR>\n" );
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document.write( "so: log(5x)=2 becomes: 5x= {10^2} (10^2 = 10 squared)<BR>\n" );
document.write( "5x= {10^2}<BR>\n" );
document.write( "5x=100<BR>\n" );
document.write( "divide both sides by 5<BR>\n" );
document.write( "x=20 </SPAN>\n" );
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