document.write( "Question 118699: log5+logx=2 \n" ); document.write( "
Algebra.Com's Answer #86839 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
log5 + logx = 2
\n" ); document.write( ":
\n" ); document.write( "Can also be written (multiply is the same as adding the logs)
\n" ); document.write( "log(5x) = 2
\n" ); document.write( ":
\n" ); document.write( "Find the antilog (10^x) of both sides
\n" ); document.write( "5x = 100
\n" ); document.write( ":
\n" ); document.write( "x = 100/5
\n" ); document.write( ":
\n" ); document.write( "x = 20
\n" ); document.write( ":
\n" ); document.write( "Check on a calculator: log(5) + log(20) = 2
\n" ); document.write( " \n" ); document.write( "
\n" );