document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118667>Question 118667</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the area of a rectangle with a length of 45 and diagonals of 51? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86795 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86795\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If we cut the rectangle in half along the diagonal, we get this triangle\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28500%2C500%2C-0.5%2C2%2C-0.5%2C3.2%2C%0D%0A%0D%0Aline%280%2C0%2C0%2C3%29%2C%0D%0Aline%280%2C3%2C2%2C0%29%2C%0D%0Aline%282%2C0%2C0%2C0%29%2C%0D%0Alocate%28-0.2%2C1.5%2Cx%29%2C%0D%0Alocate%281%2C-0.2%2C45%29%2C%0D%0Alocate%281%2C2%2C51%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Since we can see that the triangle has legs of x and 45 with a hypotenuse of 51, we can use Pythagoreans theorem to find the unknown side.\r<BR>\n" );
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document.write( "Pythagoreans theorem:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2%2Bb%5E2=c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2%2Bb%5E2=c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > where a and b are the legs of the triangle and c is the hypotenuse\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B45%5E2=51%5E2 ALIGN=MIDDLE  ALT=\"x%5E2%2B45%5E2=51%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >  Plug in a=x, b=45, and c=51. Now lets solve for x\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x++%5E+2+%2B+2+0+2+5+=+2+6+0+1 ALIGN=MIDDLE  ALT=\"+x++%5E+2+%2B+2+0+2+5+=+2+6+0+1\"   DISABLED_style= \"max-width:90%; height:auto;\" > Square each individual term\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x++%5E+2+=+2+6+0+1+-+2+0+2+5 ALIGN=MIDDLE  ALT=\"+x++%5E+2+=+2+6+0+1+-+2+0+2+5\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 2025 from both sides\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x++%5E+2+=+5+7+6 ALIGN=MIDDLE  ALT=\"+x++%5E+2+=+5+7+6\"   DISABLED_style= \"max-width:90%; height:auto;\" > Combine like terms\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s+q+r+t+%28++x++%5E+2+%29+=+s+q+r+t+%28+5+7+6+%29 ALIGN=MIDDLE  ALT=\"s+q+r+t+%28++x++%5E+2+%29+=+s+q+r+t+%28+5+7+6+%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the square root of both sides\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=24 ALIGN=MIDDLE  ALT=\"x=24\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify the square root\r<BR>\n" );
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document.write( "So the width is 24\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=24%2A45=1080 ALIGN=MIDDLE  ALT=\"A=24%2A45=1080\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now multiply 24 and 45 to get the area\r<BR>\n" );
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document.write( "So the area of the rectangle is 1080\r<BR>\n" );
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