document.write( "Question 118606: The perimeter of a rectangle is 8x+2 and the width is x+2. Express the area as a trinomial. \n" ); document.write( "
Algebra.Com's Answer #86749 by jim_thompson5910(35256)\"\" \"About 
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Let L=expression for length\r
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\n" ); document.write( "\n" ); document.write( "So we know that perimeter is\r
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\n" ); document.write( "\n" ); document.write( "\"P=2W%2B2L\"\r
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\n" ); document.write( "\n" ); document.write( "\"8x%2B2=2%28x%2B2%29%2B2L\" Now plug in \"P=8x%2B2\" and \"W=x%2B2\" \r
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\n" ); document.write( "\n" ); document.write( "\"8x%2B2=2x%2B4%2B2L\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"8x%2B2-2x=4%2B2L\" Subtract 2x from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"8x%2B2-2x-4=2L\" Subtract 4 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"6x-2=2L\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"3x-1=L\" Divide both sides by 2 to isolate L\r
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\n" ); document.write( "\n" ); document.write( "So the length of the rectangle is \"L=3x-1\"\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the length and the width to get the area:\r
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\n" ); document.write( "\n" ); document.write( "\"A=%283x-1%29%28x%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=3x%5E2%2B5x-2\" Now foil\r
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\n" ); document.write( "\n" ); document.write( "So the area is \"A=3x%5E2%2B5x-2\"
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