document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118617>Question 118617</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Kyle has 50 coins consistin of nickels and dimes.  If he has $4.15, how many of each coin does Kyle possess? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86742 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86742\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Kyle has 50 coins consistin of nickels and dimes. If he has $4.15, how many of each coin does Kyle possess?<BR>\n" );
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document.write( "Let # of nickels be \"x\" ; Value is 5x cents<BR>\n" );
document.write( "# of dimes is \"50-x\" ; Value is 10(50-x) = 500-10x cents<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "value + value = 415 cents<BR>\n" );
document.write( "5x + 500-10x = 415<BR>\n" );
document.write( "-5x = -85<BR>\n" );
document.write( "x = 17 (# of nickels)<BR>\n" );
document.write( "50-x = 33 (# of dimes)<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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