document.write( "Question 17958: a dentist invested a portion of $15,000 in a 7% annual simple interest account and the remainder in a 6.5% annual simple interest goverment bond. the two investments earn $1020 in interest annually. how much was invested in each account. \n" ); document.write( "
Algebra.Com's Answer #8674 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let x = the amount invested at 7% (= 0.07) and ($15,000 - x) the amount invested at 6.5% (= 0.065). Change the percents to decimals and then set up your equation. Solve for x:\r
\n" ); document.write( "\n" ); document.write( "\"%280.07%29x+%2B+%280.065%29%2815000-x%29+=+1020\" Simplify and solve for x.
\n" ); document.write( "\"0.07x+%2B+975+-+0.065x+=+1020\" Subtract 975 from both sides.
\n" ); document.write( "\"0.005x++=+45\" Divide both sides by 0.005
\n" ); document.write( "\"x+=+9000\"\r
\n" ); document.write( "\n" ); document.write( "The amount invested ay 7% is $9,000
\n" ); document.write( "The amount invested at 6.5% is ($15,000 - $9,000) = $6,000\r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "\"%280.07%29%289000%29+%2B+%280.065%29%286000%29+=+630+%2B+390+=+1020\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );