document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118623>Question 118623</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0078656095/algebrahomeworkh>Glenco Mathematics Algebra 2</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> log(base 10)y + log(base 10)(y+3)=1  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86726 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86726\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log(base 10)y + log(base 10)(y+3)=1 <BR>\n" );
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document.write( "log(base 10)[y(y+3)] = 1<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "Change to exponential formL<BR>\n" );
document.write( "y(y+3) = 10^1<BR>\n" );
document.write( "y^2+3y-10 = 0<BR>\n" );
document.write( "(y-5)(y+2) = 0<BR>\n" );
document.write( "y = 5 or y = -2<BR>\n" );
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document.write( "But y cannot be negative in the original equation<BR>\n" );
document.write( "so y = 5 is the only solution.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );