document.write( "Question 118598: Mindy left at 8 am and will arrive at 1 pm. Kelly left at 8 am and will arrive at 2 pm. How many miles is the trip if Kelly is traveling 10 mph slower than Mindy? \n" ); document.write( "

Algebra.Com's Answer #86724 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Mindy's time: $\"5\"$ hrs
\n" ); document.write( "Kelly's time: $\"6\"$ hrs
\n" ); document.write( "The distance is the same for both of them
\n" ); document.write( " $\"d+=+r%5Bm%5D%2At%5Bm%5D\"$ for Mindy
\n" ); document.write( " $\"d+=+r%5Bk%5D%2At%5Bk%5D\"$ for kelly
\n" ); document.write( " $\"r%5Bm%5D%2At%5Bm%5D+=+r%5Bk%5D%2At%5Bk%5D\"$
\n" ); document.write( " $\"r%5Bm%5D%2A5+=+%28r%5Bm%5D+-+10%29%2A6\"$
\n" ); document.write( " $\"r%5Bm%5D%2A5+=+r%5Bm%5D%2A6+-+60\"$
\n" ); document.write( " $\"r%5Bm%5D+=+60\"$ mi/hr
\n" ); document.write( " $\"r%5Bk%5D+=+r%5Bm%5D+-+10\"$
\n" ); document.write( " $\"r%5Bk%5D+=+60+-+10\"$
\n" ); document.write( " $\"r%5Bk%5D+=+50\"$ mi/hr
\n" ); document.write( " $\"d+=+r%5Bm%5D%2At%5Bm%5D\"$ for Mindy
\n" ); document.write( " $\"d+=+60%2A5\"$
\n" ); document.write( " $\"d+=+300\"$ mi
\n" ); document.write( " $\"d+=+r%5Bk%5D%2At%5Bk%5D\"$ for kelly
\n" ); document.write( " $\"d+=+50%2A6\"$
\n" ); document.write( " $\"d+=+300\"$ mi
\n" ); document.write( "Both ways of finding $\"d\"$ agree, so
\n" ); document.write( "distance is 300 miles \n" ); document.write( "

\n" );