document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118567>Question 118567</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "If a boat goes downstream 72 miles in 3 hours and upstream 60 miles in 6 hours, the rate of the river and the rate of the boat in still water respectively are ________? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86714 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 72/3=24 RATE GOING DOWN STREAM.<BR>\n" );
document.write( "60/6=10 RATE GOING UP STREAM.<BR>\n" );
document.write( "(24-10)/2=14/2=7 IS THE RATE OF THE RIVER.<BR>\n" );
document.write( "24-7=17 IS THE SPEED OF THE BOAT IN STILL WATER.<BR>\n" );
document.write( "10+7=17 DITTO. </SPAN>\n" );
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