document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118585>Question 118585</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618371834/algebrahomeworkh>Algebra 1</A><BR>\n" );
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document.write( "The sum of three numbers is 137.  The second number is 4 more that two times the first number.  The third number is 5 less than three times the first number.  Find the three numbers.\r<BR>\n" );
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document.write( "Thank you for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86713 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET X BE THE FIRST NUMBER<BR>\n" );
document.write( "LET (4+2X) BE THE SECOND NUMBER<BR>\n" );
document.write( "LET (3X-5) BE THE THIRD NUMBER<BR>\n" );
document.write( "THUS WE HAVE:<BR>\n" );
document.write( "X+(4+2X)+(3X-5)=137<BR>\n" );
document.write( "6X-1=137<BR>\n" );
document.write( "6X=137+1<BR>\n" );
document.write( "6X=138<BR>\n" );
document.write( "X=138/6<BR>\n" );
document.write( "X=23 ANSWER FOR THE FIRST NUMBER.<BR>\n" );
document.write( "4+2*23=4+46=50 FOR THE SECOND NUMBER.<BR>\n" );
document.write( "3*23-5=69-5=64 FOR THE THIRD NUMBER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "23+50+64=137<BR>\n" );
document.write( "137=137<BR>\n" );
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