document.write( "Question 118555: What is \"x\" in this equation?: \"%283%2F4%29%2Ax-5=4\"
\n" ); document.write( "I got 2 6/7 but i don't feel that's right.
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Algebra.Com's Answer #86688 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given:
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\n" ); document.write( "\"%283%2F4%29%2Ax+-+5+=+4\"
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\n" ); document.write( "Let's solve this and compare it with the answer you got. Sometimes its less confusing if
\n" ); document.write( "you get rid of the fraction at the start. You can do this by multiplying both sides (all terms)
\n" ); document.write( "by 4 ... When you do that in the first term on the left side the multiplier 4 cancels with
\n" ); document.write( "the denominator 4 and you are left with 3x. The -5 times 4 becomes -20. And on the right side
\n" ); document.write( "the 4 times 4 results in 16. So, putting this all together, by multiplying all terms on both
\n" ); document.write( "sides by 4 the equation is changed to:
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\n" ); document.write( "\"3x+-+20+=+16\"
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\n" ); document.write( "Get rid of the -20 on the left side by adding 20 to both sides to get:
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\n" ); document.write( "\"3x+=+36\"
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\n" ); document.write( "Solve for x by dividing both sides by 3 and the answer becomes:
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\n" ); document.write( "\"x+=+36%2F3+=+12\"
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\n" ); document.write( "So the answer is x = 12
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\n" ); document.write( "Let's check the answer by going back to the original equation:
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\n" ); document.write( "\"%283%2F4%29%2Ax-5=4\"
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\n" ); document.write( "and substituting 12 for x to get:
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\n" ); document.write( "\"%283%2F4%29%2A12+-+5+=+4\"
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\n" ); document.write( "Three-fourths of 12 is 9 so the equation is then:
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\n" ); document.write( "\"9+-+5+=+4\"
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\n" ); document.write( "This is obviously a correct statement ... 9 minus 5 does equal 4 ... so the answer of
\n" ); document.write( "x = 12 is correct.
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\n" ); document.write( "Hope this helps you to understand the problem a little better and helps you to find where you
\n" ); document.write( "might have made a mistake.
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