document.write( "Question 118542: A poster in the shape of a triangle has one side that is five inches more the length of the shortest side, and another side that is three inches less than twice the shortest side. Find the dimensions of the poster if its perimeter is 42 inches \n" ); document.write( "

Algebra.Com's Answer #86660 by josmiceli(19441) $\"\"$ $\"About$

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$\"x\"$ = shortest side
\n" ); document.write( "The sides are
\n" ); document.write( " $\"x\"$ , $\"x%2B5\"$ , $\"2x-3\"$
\n" ); document.write( " $\"x+%2B+x%2B5+%2B+2x-3+=+42\"$
\n" ); document.write( " $\"4x+%2B+2+=+42\"$
\n" ); document.write( " $\"4x+=+40\"$
\n" ); document.write( " $\"x+=+10\"$
\n" ); document.write( "The sides are
\n" ); document.write( " $\"x+=+10\"$ inches
\n" ); document.write( " $\"10%2B5+=+15\"$ inches
\n" ); document.write( " $\"2%2A10-3+=+17\"$ inches
\n" ); document.write( "check
\n" ); document.write( " $\"10+%2B+15+%2B+17+=+42\"$
\n" ); document.write( " $\"42+=+42\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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