document.write( "Question 118471This question is from textbook Algebra 1
\n" );
document.write( ": This is exactly what the instructions say: Find the resulting unit of measure.\r
\n" );
document.write( "\n" );
document.write( "51. (feet) / (second)
\n" );
document.write( "52. (centimeters) / (centimeters per yard)
\n" );
document.write( "53. (minutes per hour) * (hours)
\n" );
document.write( "54. (inches per feet) * (feet per yard)\r
\n" );
document.write( "\n" );
document.write( "My Book's ISBN # is: 0-618-37183-4
\n" );
document.write( "The Book is called: McDougal Littell Algebra 1 and it is the Florida Edition
\n" );
document.write( "Thank you. \n" );
document.write( "
Algebra.Com's Answer #86616 by stanbon(75887) ![]() You can put this solution on YOUR website! Find the resulting unit of measure. \n" ); document.write( "51. (feet) / (second) = ? \n" ); document.write( "52. (centimeters) / (centimeters per yard) = yards \n" ); document.write( "53. (minutes per hour) * (hours) = minutes \n" ); document.write( "54. (inches per feet) * (feet per yard) = inches per yard \n" ); document.write( "---------------- \n" ); document.write( "Cheers, \n" ); document.write( "stan H. \n" ); document.write( " |