document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118439>Question 118439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> pls help me...<BR>\n" );
document.write( "Given the points P(-1,-2) Q(4,2) and R(1,m) in the coordinate plane. Find the value of m so that PR + RQ is minimum...thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86576 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86576\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Plot the points P and Q on a graph.  Then construct the vertical line x = 1.  R can then be any point on that vertical line.\r<BR>\n" );
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document.write( "If R is any point that is NOT on line PQ, then PQR forms a triangle and PR + RQ  > PQ.  But, if R is colinear with P and Q, then PR + RQ = PQ.  Lastly, there is no possible value for m that would create a situation where PR + RQ < PQ.  Therefore, the minimum value for m is the point where R is colinear with P and Q.\r<BR>\n" );
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document.write( "Now all you have to do is find the equation for the line containing P and Q and evaluate it at x = 1 to find your value for m.  I assume that you know the two-point form of a straight line, and leave the rest to you.  If you are still having trouble, write back and we'll work it out.\r<BR>\n" );
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document.write( "Hope that helps,<BR>\n" );
document.write( "John </SPAN>\n" );
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